Solve problems involving the calculation and conversion of units of measure 6 - Reasoning

Tia, Esin, and Leanna have each recorded the time it took them to complete their homework, which adds up to a total of 35.3 minutes. To determine the time each person needed individually, we must consider the additional information provided: Tia took 150 seconds more than Leanna, and Esin took 3.3 minutes more than Tia. To solve this, we first convert the extra time Tia took from seconds to minutes, as the total time is given in minutes. Since there are 60 seconds in a minute, 150 seconds is equivalent to 2.5 minutes. Now, we can denote Leanna's time as 'L' minutes, which makes Tia's time 'L + 2.5' minutes and Esin's time 'L + 2.5 + 3.3' minutes.

Adding these three times together gives us the total time of 35.3 minutes, which can be expressed as an equation: L + (L + 2.5) + (L + 2.5 + 3.3) = 35.3. Simplifying this equation, we find that 3L + 8.3 = 35.3. Solving for L gives us Leanna's time as 9 minutes. Subsequently, Tia's time is 9 + 2.5 = 11.5 minutes, and Esin's time is 11.5 + 3.3 = 14.8 minutes. Therefore, we have determined the individual times required for each of them to complete their homework: Tia needed 11.5 minutes, Esin needed 14.8 minutes, and Leanna needed 9 minutes.